Batch file to shutdown system one day a week, hibernate it other days

latimer · 01 Mar 2023

Version 22H2.

I need to properly code a batch file to shutdown my system one day a week (I've chosen Wednesdays), and hibernate it other days.

I am aware of "shutdown /h" and "shutdown /s /hybrid" but want to know how to create the variable for the day of the week (numeric or string), and format the "if" command to run when the variable matches.

garlin · 01 Mar 2023

Code:

@echo off

for /f "tokens=1" %%i IN ('date /t') do set TODAY=%%i
if %TODAY% == Wed (
   echo Wednesday
) else (
   echo Not Wednesday
)

Bree · 01 Mar 2023

latimer said:

Version 22H2.

I need to properly code a batch file to shutdown my system one day a week (I've chosen Wednesdays), and hibernate it other days.

I am aware of "shutdown /h" and "shutdown /s /hybrid" but want to know how to create the variable for the day of the week (numeric or string), and format the "if" command to run when the variable matches.

The problem with using the DATE command is that what you get can vary depending on the regional date format your system uses. Instead of using DATE try this:

Here's the correct answer for a BAT script on a modern system:

@echo off

for /f %%i in ('powershell ^(get-date^).DayOfWeek') do set dow=%%i

echo %dow%

Outputs:

Saturday

Finding day of week in batch file? (Windows Server 2008) - Server Fault

Try3 · 02 Mar 2023

I suggest you just use Task scheduler to run the required commands on the required days.

Denis