Programming Chalagens

I've been doing these in Python but any language can be used.

1. love6

The number 6 is a truly great number. Given two int values, a and b, return True if either one is 6. Or if their sum or difference is 6. Note: the function abs(num) computes the absolute value of a number.

love6(6, 4) → True
love6(4, 5) → False
love6(1, 5) → True

Solution in Python version 2.7.9

PHP Code:

def love6(a, b):
    if (a == 6 or b == 6):
        return True
    elif (a + b == 6):
        return True
    elif (abs(a - b) == 6):
        return True
    else:
        return False 


Results of Test;

2. caught_speeding:

You are driving a little too fast, and a police officer stops you. Write code to compute the result, encoded as an int value: 0=no ticket, 1=small ticket, 2=big ticket. If speed is 60 or less, the result is 0. If speed is between 61 and 80 inclusive, the result is 1. If speed is 81 or more, the result is 2. Unless it is your birthday -- on that day, your speed can be 5 higher in all cases.

caught_speeding(60, False) → 0
caught_speeding(65, False) → 1
caught_speeding(65, True) → 0

Solution in Python 2.7.9:

PHP Code:

def caught_speeding(speed, is_birthday):
    ticket = int(0)

    if is_birthday:
        if speed >= 66 and speed <= 85:
            ticket = 1
        elif speed >= 86:
            ticket = 2
    else:
        if speed >= 61 and speed <= 81:
            ticket = 1
        elif speed >= 81:
            ticket = 2

    return ticket 


Results of Test:

3. cigar_party..

When squirrels get together for a party, they like to have cigars. A squirrel party is successful when the number of cigars is between 40 and 60, inclusive. Unless it is the weekend, in which case there is no upper bound on the number of cigars. Return True if the party with the given values is successful, or False otherwise.

cigar_party(30, False) → False
cigar_party(50, False) → True
cigar_party(70, True) → True

Solution in Python version 2.7.9:

PHP Code:

def cigar_party(cigars, is_weekend):

    if (is_weekend and cigars >= 40): return True
    if (cigars >= 40 and cigars <= 60): return True
    return False 


Results of test:

4. first_half.py

Given a string of even length, return the first half. So the string "WooHoo" yields "Woo".

first_half('WooHoo') → 'Woo'
first_half('HelloThere') → 'Hello'
first_half('abcdef') → 'abc'

Solution in Python 2.7.9

PHP Code:

def first_half(str):
    length = (len(str) / 2)
    return str[0:length] 


Results:

5. first_two.py

Given a string, return the string made of its first two chars, so the String "Hello" yields "He". If the string is shorter than length 2, return whatever there is, so "X" yields "X", and the empty string "" yields the empty string "".

first_two('Hello') → 'He'
first_two('abcdefg') → 'ab'
first_two('ab') → 'ab'

Solution in Python 2.7.9:

PHP Code:

def first_two(str):
    return str[0:2] 


Results:

6. make_tags.py

The web is built with HTML strings like "<i>Yay</i>" which draws Yay as italic text. In this example, the "i" tag makes <i> and </i> which surround the word "Yay". Given tag and word strings, create the HTML string with tags around the word, e.g. "<i>Yay</i>".

make_tags('i', 'Yay') → '<i>Yay</i>'
make_tags('i', 'Hello') → '<i>Hello</i>'
make_tags('cite', 'Yay') → '<cite>Yay</cite>'

Solution in Python 2.7.9:

PHP Code:

def make_tags(tag, word):
    return "<{0}>{1}</{0}>".format(tag,word)

#----------------------------------
print make_tags('i', 'Yay')
print make_tags('i', 'Hello')
print make_tags('cite', 'Yay') 


Results:

7. extra_end.py

Given a string, return a new string made of 3 copies of the last 2 chars of the original string. The string length will be at least 2.

extra_end('Hello') → 'lololo'
extra_end('ab') → 'ababab'
extra_end('Hi') → 'HiHiHi'

Solution in Python 2.7.9:

PHP Code:

def extra_end(str):
    return str[len(str) - 2:len(str)+1] * 3
#-------------------------------------
print extra_end('Hello')
print extra_end('ab')
print extra_end('Hi') 


Result: